struct Dictionary A collection whose elements are key-value pairs. Inheritance Collection, CustomDebugStringConvertible, CustomReflectable, CustomStringConvertible, ExpressibleByDictionaryLiteral, Sequence Associated Types public typealias Element = (key: Key, value: Value) public typealias Element = Key public typealias SubSequence = Slice<Dictionary<Key, Value>.Keys> This associated type appears as a requirement in the Sequence protocol, but it is restated here with stricter constraints. In a collection, the subsequence should also conform to Collection. public typealias Element = Value public typealias SubSequence = Slice<[Key : Value]> This associated type appears as a requirement in the Sequence protocol, but it is restated here with stricter constraints. In a collection, the subsequence should also conform to Collection. Nested Types Dictionary.Keys, Dictionary.Values, Dictionary.Index, Dictionary.Iterator A dictionary is a type of hash table, providing fast access to the entries it contains. Each entry in the table is identified using its key, which is a hashable type such as a string or number. You use that key to retrieve the corresponding value, which can be any object. In other languages, similar data types are known as hashes or associated arrays. Create a new dictionary by using a dictionary literal. A dictionary literal is a comma-separated list of key-value pairs, in which a colon separates each key from its associated value, surrounded by square brackets. You can assign a dictionary literal to a variable or constant or pass it to a function that expects a dictionary. Here's how you would create a dictionary of HTTP response codes and their related messages: var responseMessages = [200: "OK", 403: "Access forbidden", 404: "File not found", 500: "Internal server error"] The responseMessages variable is inferred to have type [Int: String]. The Key type of the dictionary is Int, and the Value type of the dictionary is String. To create a dictionary with no key-value pairs, use an empty dictionary literal ([:]). var emptyDict: [String: String] = [:] Any type that conforms to the Hashable protocol can be used as a dictionary's Key type, including all of Swift's basic types. You can use your own custom types as dictionary keys by making them conform to the Hashable protocol. Getting and Setting Dictionary Values The most common way to access values in a dictionary is to use a key as a subscript. Subscripting with a key takes the following form: print(responseMessages[200]) // Prints "Optional("OK")" Subscripting a dictionary with a key returns an optional value, because a dictionary might not hold a value for the key that you use in the subscript. The next example uses key-based subscripting of the responseMessages dictionary with two keys that exist in the dictionary and one that does not. let httpResponseCodes = [200, 403, 301] for code in httpResponseCodes { if let message = responseMessages[code] { print("Response \(code): \(message)") } else { print("Unknown response \(code)") } } // Prints "Response 200: OK" // Prints "Response 403: Access Forbidden" // Prints "Unknown response 301" You can also update, modify, or remove keys and values from a dictionary using the key-based subscript. To add a new key-value pair, assign a value to a key that isn't yet a part of the dictionary. responseMessages[301] = "Moved permanently" print(responseMessages[301]) // Prints "Optional("Moved permanently")" Update an existing value by assigning a new value to a key that already exists in the dictionary. If you assign nil to an existing key, the key and its associated value are removed. The following example updates the value for the 404 code to be simply "Not found" and removes the key-value pair for the 500 code entirely. responseMessages[404] = "Not found" responseMessages[500] = nil print(responseMessages) // Prints "[301: "Moved permanently", 200: "OK", 403: "Access forbidden", 404: "Not found"]" In a mutable Dictionary instance, you can modify in place a value that you've accessed through a keyed subscript. The code sample below declares a dictionary called interestingNumbers with string keys and values that are integer arrays, then sorts each array in-place in descending order. var interestingNumbers = ["primes": [2, 3, 5, 7, 11, 13, 17], "triangular": [1, 3, 6, 10, 15, 21, 28], "hexagonal": [1, 6, 15, 28, 45, 66, 91]] for key in interestingNumbers.keys { interestingNumbers[key]?.sort(by: >) } print(interestingNumbers["primes"]!) // Prints "[17, 13, 11, 7, 5, 3, 2]" Iterating Over the Contents of a Dictionary Every dictionary is an unordered collection of key-value pairs. You can iterate over a dictionary using a for-in loop, decomposing each key-value pair into the elements of a tuple. let imagePaths = ["star": "/glyphs/star.png", "portrait": "/images/content/portrait.jpg", "spacer": "/images/shared/spacer.gif"] for (name, path) in imagePaths { print("The path to '\(name)' is '\(path)'.") } // Prints "The path to 'star' is '/glyphs/star.png'." // Prints "The path to 'portrait' is '/images/content/portrait.jpg'." // Prints "The path to 'spacer' is '/images/shared/spacer.gif'." The order of key-value pairs in a dictionary is stable between mutations but is otherwise unpredictable. If you need an ordered collection of key-value pairs and don't need the fast key lookup that Dictionary provides, see the KeyValuePairs type for an alternative. You can search a dictionary's contents for a particular value using the contains(where:) or firstIndex(where:) methods supplied by default implementation. The following example checks to see if imagePaths contains any paths in the "/glyphs" directory: let glyphIndex = imagePaths.firstIndex(where: { $0.value.hasPrefix("/glyphs") }) if let index = glyphIndex { print("The '\(imagePaths[index].key)' image is a glyph.") } else { print("No glyphs found!") } // Prints "The 'star' image is a glyph.") Note that in this example, imagePaths is subscripted using a dictionary index. Unlike the key-based subscript, the index-based subscript returns the corresponding key-value pair as a non-optional tuple. print(imagePaths[glyphIndex!]) // Prints "("star", "/glyphs/star.png")" A dictionary's indices stay valid across additions to the dictionary as long as the dictionary has enough capacity to store the added values without allocating more buffer. When a dictionary outgrows its buffer, existing indices may be invalidated without any notification. When you know how many new values you're adding to a dictionary, use the init(minimumCapacity:) initializer to allocate the correct amount of buffer. Bridging Between Dictionary and NSDictionary You can bridge between Dictionary and NSDictionary using the as operator. For bridging to be possible, the Key and Value types of a dictionary must be classes, @objc protocols, or types that bridge to Foundation types. Bridging from Dictionary to NSDictionary always takes O(1) time and space. When the dictionary's Key and Value types are neither classes nor @objc protocols, any required bridging of elements occurs at the first access of each element. For this reason, the first operation that uses the contents of the dictionary may take O(n). Bridging from NSDictionary to Dictionary first calls the copy(with:) method (- copyWithZone: in Objective-C) on the dictionary to get an immutable copy and then performs additional Swift bookkeeping work that takes O(1) time. For instances of NSDictionary that are already immutable, copy(with:) usually returns the same dictionary in O(1) time; otherwise, the copying performance is unspecified. The instances of NSDictionary and Dictionary share buffer using the same copy-on-write optimization that is used when two instances of Dictionary share buffer. Initializers init init() Required Creates an empty dictionary. Declaration @inlinable public init() init init(_:uniquingKeysWith:) Required Creates a new dictionary from the key-value pairs in the given sequence, using a combining closure to determine the value for any duplicate keys. You use this initializer to create a dictionary when you have a sequence of key-value tuples that might have duplicate keys. As the dictionary is built, the initializer calls the combine closure with the current and new values for any duplicate keys. Pass a closure as combine that returns the value to use in the resulting dictionary: The closure can choose between the two values, combine them to produce a new value, or even throw an error. The following example shows how to choose the first and last values for any duplicate keys: let pairsWithDuplicateKeys = [("a", 1), ("b", 2), ("a", 3), ("b", 4)] let firstValues = Dictionary(pairsWithDuplicateKeys, uniquingKeysWith: { (first, _) in first }) // ["b": 2, "a": 1] let lastValues = Dictionary(pairsWithDuplicateKeys, uniquingKeysWith: { (_, last) in last }) // ["b": 4, "a": 3] Declaration @inlinable public init<S>(_ keysAndValues: S, uniquingKeysWith combine: (Value, Value) throws -> Value) rethrows where S: Sequence, S.Element == (Key, Value) init init(dictionaryLiteral:) Required Creates a dictionary initialized with a dictionary literal. Do not call this initializer directly. It is called by the compiler to handle dictionary literals. To use a dictionary literal as the initial value of a dictionary, enclose a comma-separated list of key-value pairs in square brackets. For example, the code sample below creates a dictionary with string keys and values. let countryCodes = ["BR": "Brazil", "GH": "Ghana", "JP": "Japan"] print(countryCodes) // Prints "["BR": "Brazil", "JP": "Japan", "GH": "Ghana"]" Parameter elements: The key-value pairs that will make up the new dictionary. Each key in elements must be unique. Declaration @inlinable public init(dictionaryLiteral elements: (Key, Value)) init init(grouping:by:) Required Creates a new dictionary whose keys are the groupings returned by the given closure and whose values are arrays of the elements that returned each key. The arrays in the "values" position of the new dictionary each contain at least one element, with the elements in the same order as the source sequence. The following example declares an array of names, and then creates a dictionary from that array by grouping the names by first letter: let students = ["Kofi", "Abena", "Efua", "Kweku", "Akosua"] let studentsByLetter = Dictionary(grouping: students, by: { $0.first! }) // ["E": ["Efua"], "K": ["Kofi", "Kweku"], "A": ["Abena", "Akosua"]] The new studentsByLetter dictionary has three entries, with students' names grouped by the keys "E", "K", and "A". Declaration @inlinable public init<S>(grouping values: S, by keyForValue: (S.Element) throws -> Key) rethrows where Value == [S.Element], S: Sequence init init(minimumCapacity:) Required Creates an empty dictionary with preallocated space for at least the specified number of elements. Use this initializer to avoid intermediate reallocations of a dictionary's storage buffer when you know how many key-value pairs you are adding to a dictionary after creation. Parameter minimumCapacity: The minimum number of key-value pairs that the newly created dictionary should be able to store without reallocating its storage buffer. Declaration public init(minimumCapacity: Int) init init(uniqueKeysWithValues:) Required Creates a new dictionary from the key-value pairs in the given sequence. You use this initializer to create a dictionary when you have a sequence of key-value tuples with unique keys. Passing a sequence with duplicate keys to this initializer results in a runtime error. If your sequence might have duplicate keys, use the Dictionary(_:uniquingKeysWith:) initializer instead. The following example creates a new dictionary using an array of strings as the keys and the integers in a countable range as the values: let digitWords = ["one", "two", "three", "four", "five"] let wordToValue = Dictionary(uniqueKeysWithValues: zip(digitWords, 1...5)) print(wordToValue["three"]!) // Prints "3" print(wordToValue) // Prints "["three": 3, "four": 4, "five": 5, "one": 1, "two": 2]" Parameter keysAndValues: A sequence of key-value pairs to use for the new dictionary. Every key in keysAndValues must be unique. Precondition: The sequence must not have duplicate keys. Declaration @inlinable public init<S>(uniqueKeysWithValues keysAndValues: S) where S: Sequence, S.Element == (Key, Value) Instance Variables var capacity Required The total number of key-value pairs that the dictionary can contain without allocating new storage. Declaration var capacity: Int var count Required The number of keys in the dictionary. Complexity: O(1). Declaration var count: Int var count Required The number of values in the dictionary. Complexity: O(1). Declaration var count: Int var count Required The number of elements in the collection. To check whether a collection is empty, use its isEmpty property instead of comparing count to zero. Unless the collection guarantees random-access performance, calculating count can be an O(n) operation. Complexity: O(1) if the collection conforms to RandomAccessCollection; otherwise, O(n), where n is the length of the collection. Declaration var count: Int var count Required The number of key-value pairs in the dictionary. Complexity: O(1). Declaration var count: Int var customMirror Required A mirror that reflects the dictionary. Declaration var customMirror: Mirror var debugDescription Required A textual representation of this instance, suitable for debugging. Calling this property directly is discouraged. Instead, convert an instance of any type to a string by using the String(reflecting:) initializer. This initializer works with any type, and uses the custom debugDescription property for types that conform to CustomDebugStringConvertible: struct Point: CustomDebugStringConvertible { let x: Int, y: Int var debugDescription: String { return "(\(x), \(y))" } } let p = Point(x: 21, y: 30) let s = String(reflecting: p) print(s) // Prints "(21, 30)" The conversion of p to a string in the assignment to s uses the Point type's debugDescription property. Declaration var debugDescription: String var debugDescription Required A textual representation of this instance, suitable for debugging. Calling this property directly is discouraged. Instead, convert an instance of any type to a string by using the String(reflecting:) initializer. This initializer works with any type, and uses the custom debugDescription property for types that conform to CustomDebugStringConvertible: struct Point: CustomDebugStringConvertible { let x: Int, y: Int var debugDescription: String { return "(\(x), \(y))" } } let p = Point(x: 21, y: 30) let s = String(reflecting: p) print(s) // Prints "(21, 30)" The conversion of p to a string in the assignment to s uses the Point type's debugDescription property. Declaration var debugDescription: String var debugDescription Required A string that represents the contents of the dictionary, suitable for debugging. Declaration var debugDescription: String var description Required A textual representation of this instance. Calling this property directly is discouraged. Instead, convert an instance of any type to a string by using the String(describing:) initializer. This initializer works with any type, and uses the custom description property for types that conform to CustomStringConvertible: struct Point: CustomStringConvertible { let x: Int, y: Int var description: String { return "(\(x), \(y))" } } let p = Point(x: 21, y: 30) let s = String(describing: p) print(s) // Prints "(21, 30)" The conversion of p to a string in the assignment to s uses the Point type's description property. Declaration var description: String var description Required A textual representation of this instance. Calling this property directly is discouraged. Instead, convert an instance of any type to a string by using the String(describing:) initializer. This initializer works with any type, and uses the custom description property for types that conform to CustomStringConvertible: struct Point: CustomStringConvertible { let x: Int, y: Int var description: String { return "(\(x), \(y))" } } let p = Point(x: 21, y: 30) let s = String(describing: p) print(s) // Prints "(21, 30)" The conversion of p to a string in the assignment to s uses the Point type's description property. Declaration var description: String var description Required A string that represents the contents of the dictionary. Declaration var description: String var endIndex Required The collection's "past the end" position---that is, the position one greater than the last valid subscript argument. When you need a range that includes the last element of a collection, use the half-open range operator (..<) with endIndex. The ..< operator creates a range that doesn't include the upper bound, so it's always safe to use with endIndex. For example: let numbers = [10, 20, 30, 40, 50] if let index = numbers.firstIndex(of: 30) { print(numbers[index ..< numbers.endIndex]) } // Prints "[30, 40, 50]" If the collection is empty, endIndex is equal to startIndex. Declaration var endIndex: Dictionary<Key, Value>.Index var endIndex Required The collection's "past the end" position---that is, the position one greater than the last valid subscript argument. When you need a range that includes the last element of a collection, use the half-open range operator (..<) with endIndex. The ..< operator creates a range that doesn't include the upper bound, so it's always safe to use with endIndex. For example: let numbers = [10, 20, 30, 40, 50] if let index = numbers.firstIndex(of: 30) { print(numbers[index ..< numbers.endIndex]) } // Prints "[30, 40, 50]" If the collection is empty, endIndex is equal to startIndex. Declaration var endIndex: Dictionary<Key, Value>.Index var endIndex Required The dictionary's "past the end" position---that is, the position one greater than the last valid subscript argument. If the collection is empty, endIndex is equal to startIndex. Complexity: Amortized O(1) if the dictionary does not wrap a bridged NSDictionary; otherwise, the performance is unspecified. Declaration var endIndex: Dictionary<Key, Value>.Index var first Required The first element of the collection. If the collection is empty, the value of this property is nil. let numbers = [10, 20, 30, 40, 50] if let firstNumber = numbers.first { print(firstNumber) } // Prints "10" Declaration var first: Self.Element? var isEmpty Required A Boolean value indicating whether the collection is empty. When you need to check whether your collection is empty, use the isEmpty property instead of checking that the count property is equal to zero. For collections that don't conform to RandomAccessCollection, accessing the count property iterates through the elements of the collection. let horseName = "Silver" if horseName.isEmpty { print("I've been through the desert on a horse with no name.") } else { print("Hi ho, \(horseName)!") } // Prints "Hi ho, Silver!" Complexity: O(1) Declaration var isEmpty: Bool var isEmpty Required A Boolean value indicating whether the collection is empty. When you need to check whether your collection is empty, use the isEmpty property instead of checking that the count property is equal to zero. For collections that don't conform to RandomAccessCollection, accessing the count property iterates through the elements of the collection. let horseName = "Silver" if horseName.isEmpty { print("I've been through the desert on a horse with no name.") } else { print("Hi ho, \(horseName)!") } // Prints "Hi ho, Silver!" Complexity: O(1) Declaration var isEmpty: Bool var isEmpty Required A Boolean value indicating whether the collection is empty. When you need to check whether your collection is empty, use the isEmpty property instead of checking that the count property is equal to zero. For collections that don't conform to RandomAccessCollection, accessing the count property iterates through the elements of the collection. let horseName = "Silver" if horseName.isEmpty { print("I've been through the desert on a horse with no name.") } else { print("Hi ho, \(horseName)!") } // Prints "Hi ho, Silver!") Complexity: O(1) Declaration var isEmpty: Bool var isEmpty Required A Boolean value that indicates whether the dictionary is empty. Dictionaries are empty when created with an initializer or an empty dictionary literal. var frequencies: [String: Int] = [:] print(frequencies.isEmpty) // Prints "true" Declaration var isEmpty: Bool var keys Required A collection containing just the keys of the dictionary. When iterated over, keys appear in this collection in the same order as they occur in the dictionary's key-value pairs. Each key in the keys collection has a unique value. let countryCodes = ["BR": "Brazil", "GH": "Ghana", "JP": "Japan"] print(countryCodes) // Prints "["BR": "Brazil", "JP": "Japan", "GH": "Ghana"]" for k in countryCodes.keys { print(k) } // Prints "BR" // Prints "JP" // Prints "GH" Declaration var keys: Dictionary<Key, Value>.Keys var lazy Required A sequence containing the same elements as this sequence, but on which some operations, such as map and filter, are implemented lazily. Declaration var lazy: LazySequence<Self> var startIndex Required The position of the first element in a nonempty collection. If the collection is empty, startIndex is equal to endIndex. Declaration var startIndex: Dictionary<Key, Value>.Index var startIndex Required The position of the first element in a nonempty collection. If the collection is empty, startIndex is equal to endIndex. Declaration var startIndex: Dictionary<Key, Value>.Index var startIndex Required The position of the first element in a nonempty dictionary. If the collection is empty, startIndex is equal to endIndex. Complexity: Amortized O(1) if the dictionary does not wrap a bridged NSDictionary. If the dictionary wraps a bridged NSDictionary, the performance is unspecified. Declaration var startIndex: Dictionary<Key, Value>.Index var underestimatedCount Required A value less than or equal to the number of elements in the sequence, calculated nondestructively. The default implementation returns 0. If you provide your own implementation, make sure to compute the value nondestructively. Complexity: O(1), except if the sequence also conforms to Collection. In this case, see the documentation of Collection.underestimatedCount. Declaration var underestimatedCount: Int var underestimatedCount Required A value less than or equal to the number of elements in the collection. Complexity: O(1) if the collection conforms to RandomAccessCollection; otherwise, O(n), where n is the length of the collection. Declaration var underestimatedCount: Int var values Required A collection containing just the values of the dictionary. When iterated over, values appear in this collection in the same order as they occur in the dictionary's key-value pairs. let countryCodes = ["BR": "Brazil", "GH": "Ghana", "JP": "Japan"] print(countryCodes) // Prints "["BR": "Brazil", "JP": "Japan", "GH": "Ghana"]" for v in countryCodes.values { print(v) } // Prints "Brazil" // Prints "Japan" // Prints "Ghana" Declaration var values: Dictionary<Key, Value>.Values Subscripts subscript subscript(key:) Required Accesses the value associated with the given key for reading and writing. This key-based subscript returns the value for the given key if the key is found in the dictionary, or nil if the key is not found. The following example creates a new dictionary and prints the value of a key found in the dictionary ("Coral") and a key not found in the dictionary ("Cerise"). var hues = ["Heliotrope": 296, "Coral": 16, "Aquamarine": 156] print(hues["Coral"]) // Prints "Optional(16)" print(hues["Cerise"]) // Prints "nil" When you assign a value for a key and that key already exists, the dictionary overwrites the existing value. If the dictionary doesn't contain the key, the key and value are added as a new key-value pair. Here, the value for the key "Coral" is updated from 16 to 18 and a new key-value pair is added for the key "Cerise". hues["Coral"] = 18 print(hues["Coral"]) // Prints "Optional(18)" hues["Cerise"] = 330 print(hues["Cerise"]) // Prints "Optional(330)" If you assign nil as the value for the given key, the dictionary removes that key and its associated value. In the following example, the key-value pair for the key "Aquamarine" is removed from the dictionary by assigning nil to the key-based subscript. hues["Aquamarine"] = nil print(hues) // Prints "["Coral": 18, "Heliotrope": 296, "Cerise": 330]" Parameter key: The key to find in the dictionary. Declaration @inlinable public subscript(key: Key) -> Value? subscript subscript(key:default:) Required Accesses the value with the given key. If the dictionary doesn't contain the given key, accesses the provided default value as if the key and default value existed in the dictionary. Use this subscript when you want either the value for a particular key or, when that key is not present in the dictionary, a default value. This example uses the subscript with a message to use in case an HTTP response code isn't recognized: var responseMessages = [200: "OK", 403: "Access forbidden", 404: "File not found", 500: "Internal server error"] let httpResponseCodes = [200, 403, 301] for code in httpResponseCodes { let message = responseMessages[code, default: "Unknown response"] print("Response \(code): \(message)") } // Prints "Response 200: OK" // Prints "Response 403: Access Forbidden" // Prints "Response 301: Unknown response" When a dictionary's Value type has value semantics, you can use this subscript to perform in-place operations on values in the dictionary. The following example uses this subscript while counting the occurrences of each letter in a string: let message = "Hello, Elle!" var letterCounts: [Character: Int] = [:] for letter in message { letterCounts[letter, defaultValue: 0] += 1 } // letterCounts == ["H": 1, "e": 2, "l": 4, "o": 1, ...] When letterCounts[letter, defaultValue: 0] += 1 is executed with a value of letter that isn't already a key in letterCounts, the specified default value (0) is returned from the subscript, incremented, and then added to the dictionary under that key. Note: Do not use this subscript to modify dictionary values if the dictionary's Value type is a class. In that case, the default value and key are not written back to the dictionary after an operation. Declaration @inlinable public subscript(key: Key, default defaultValue: @autoclosure () -> Value) -> Value subscript subscript(position:) Required Accesses the element at the specified position. The following example accesses an element of an array through its subscript to print its value: var streets = ["Adams", "Bryant", "Channing", "Douglas", "Evarts"] print(streets[1]) // Prints "Bryant" You can subscript a collection with any valid index other than the collection's end index. The end index refers to the position one past the last element of a collection, so it doesn't correspond with an element. Parameter position: The position of the element to access. position must be a valid index of the collection that is not equal to the endIndex property. Complexity: O(1) Declaration @inlinable public subscript(position: Dictionary<Key, Value>.Index) -> Dictionary<Key, Value>.Keys.Element subscript subscript(position:) Required Accesses the element at the specified position. For example, you can replace an element of an array by using its subscript. var streets = ["Adams", "Bryant", "Channing", "Douglas", "Evarts"] streets[1] = "Butler" print(streets[1]) // Prints "Butler" You can subscript a collection with any valid index other than the collection's end index. The end index refers to the position one past the last element of a collection, so it doesn't correspond with an element. Parameter position: The position of the element to access. position must be a valid index of the collection that is not equal to the endIndex property. Complexity: O(1) Declaration @inlinable public subscript(position: Dictionary<Key, Value>.Index) -> Dictionary<Key, Value>.Values.Element subscript subscript(position:) Required Accesses the key-value pair at the specified position. This subscript takes an index into the dictionary, instead of a key, and returns the corresponding key-value pair as a tuple. When performing collection-based operations that return an index into a dictionary, use this subscript with the resulting value. For example, to find the key for a particular value in a dictionary, use the firstIndex(where:) method. let countryCodes = ["BR": "Brazil", "GH": "Ghana", "JP": "Japan"] if let index = countryCodes.firstIndex(where: { $0.value == "Japan" }) { print(countryCodes[index]) print("Japan's country code is '\(countryCodes[index].key)'.") } else { print("Didn't find 'Japan' as a value in the dictionary.") } // Prints "("JP", "Japan")" // Prints "Japan's country code is 'JP'." Parameter position: The position of the key-value pair to access. position must be a valid index of the dictionary and not equal to endIndex. Declaration @inlinable public subscript(position: Dictionary<Key, Value>.Index) -> Dictionary<Key, Value>.Element subscript subscript(r:) Required Accesses the contiguous subrange of the collection's elements specified by a range expression. The range expression is converted to a concrete subrange relative to this collection. For example, using a PartialRangeFrom range expression with an array accesses the subrange from the start of the range expression until the end of the array. let streets = ["Adams", "Bryant", "Channing", "Douglas", "Evarts"] let streetsSlice = streets[2...] print(streetsSlice) // ["Channing", "Douglas", "Evarts"] The accessed slice uses the same indices for the same elements as the original collection uses. This example searches streetsSlice for one of the strings in the slice, and then uses that index in the original array. let index = streetsSlice.firstIndex(of: "Evarts") // 4 print(streets[index!]) // "Evarts" Always use the slice's startIndex property instead of assuming that its indices start at a particular value. Attempting to access an element by using an index outside the bounds of the slice's indices may result in a runtime error, even if that index is valid for the original collection. print(streetsSlice.startIndex) // 2 print(streetsSlice[2]) // "Channing" print(streetsSlice[0]) // error: Index out of bounds Parameter bounds: A range of the collection's indices. The bounds of the range must be valid indices of the collection. Complexity: O(1) Declaration @inlinable public subscript<R>(r: R) where R: RangeExpression, Self.Index == R.Bound -> Self.SubSequence subscript subscript(x:) Required Declaration @inlinable public subscript(x: (UnboundedRange_) -> ()) -> Self.SubSequence Instance Methods func allSatisfy(_ predicate: (Self.Element) throws -> Bool) rethrows -> Bool Required Returns a Boolean value indicating whether every element of a sequence satisfies a given predicate. The following code uses this method to test whether all the names in an array have at least five characters: let names = ["Sofia", "Camilla", "Martina", "Mateo", "Nicolás"] let allHaveAtLeastFive = names.allSatisfy({ $0.count >= 5 }) // allHaveAtLeastFive == true Parameter predicate: A closure that takes an element of the sequence as its argument and returns a Boolean value that indicates whether the passed element satisfies a condition. Complexity: O(n), where n is the length of the sequence. Declaration @inlinable public func allSatisfy(_ predicate: (Self.Element) throws -> Bool) rethrows -> Bool func compactMap(_ transform: (Self.Element) throws -> ElementOfResult?) rethrows -> [ElementOfResult] Required Returns an array containing the non-nil results of calling the given transformation with each element of this sequence. Use this method to receive an array of non-optional values when your transformation produces an optional value. In this example, note the difference in the result of using map and compactMap with a transformation that returns an optional Int value. let possibleNumbers = ["1", "2", "three", "///4///", "5"] let mapped: [Int?] = possibleNumbers.map { str in Int(str) } // [1, 2, nil, nil, 5] let compactMapped: [Int] = possibleNumbers.compactMap { str in Int(str) } // [1, 2, 5] Parameter transform: A closure that accepts an element of this sequence as its argument and returns an optional value. Complexity: O(m + n), where n is the length of this sequence and m is the length of the result. Declaration @inlinable public func compactMap<ElementOfResult>(_ transform: (Self.Element) throws -> ElementOfResult?) rethrows -> [ElementOfResult] func compactMapValues(_ transform: (Value) throws -> T?) rethrows -> [Key : T] Required Returns a new dictionary containing only the key-value pairs that have non-nil values as the result of transformation by the given closure. Use this method to receive a dictionary with non-optional values when your transformation produces optional values. In this example, note the difference in the result of using mapValues and compactMapValues with a transformation that returns an optional Int value. let data = ["a": "1", "b": "three", "c": "///4///"] let m: [String: Int?] = data.mapValues { str in Int(str) } // ["a": 1, "b": nil, "c": nil] let c: [String: Int] = data.compactMapValues { str in Int(str) } // ["a": 1] Parameter transform: A closure that transforms a value. transform accepts each value of the dictionary as its parameter and returns an optional transformed value of the same or of a different type. Complexity: O(m + n), where n is the length of the original dictionary and m is the length of the resulting dictionary. Declaration @inlinable public func compactMapValues<T>(_ transform: (Value) throws -> T?) rethrows -> [Key : T] func contains(where predicate: (Self.Element) throws -> Bool) rethrows -> Bool Required Returns a Boolean value indicating whether the sequence contains an element that satisfies the given predicate. You can use the predicate to check for an element of a type that doesn't conform to the Equatable protocol, such as the HTTPResponse enumeration in this example. enum HTTPResponse { case ok case error(Int) } let lastThreeResponses: [HTTPResponse] = [.ok, .ok, .error(404)] let hadError = lastThreeResponses.contains { element in if case .error = element { return true } else { return false } } // 'hadError' == true Alternatively, a predicate can be satisfied by a range of Equatable elements or a general condition. This example shows how you can check an array for an expense greater than $100. let expenses = [21.37, 55.21, 9.32, 10.18, 388.77, 11.41] let hasBigPurchase = expenses.contains { $0 > 100 } // 'hasBigPurchase' == true Parameter predicate: A closure that takes an element of the sequence as its argument and returns a Boolean value that indicates whether the passed element represents a match. Complexity: O(n), where n is the length of the sequence. Declaration @inlinable public func contains(where predicate: (Self.Element) throws -> Bool) rethrows -> Bool func distance(from start: Self.Index, to end: Self.Index) -> Int Required Returns the distance between two indices. Unless the collection conforms to the BidirectionalCollection protocol, start must be less than or equal to end. Complexity: O(1) if the collection conforms to RandomAccessCollection; otherwise, O(k), where k is the resulting distance. Declaration @inlinable public func distance(from start: Self.Index, to end: Self.Index) -> Int func drop(while predicate: (Self.Element) throws -> Bool) rethrows -> DropWhileSequence<Self> Required Returns a sequence by skipping the initial, consecutive elements that satisfy the given predicate. The following example uses the drop(while:) method to skip over the positive numbers at the beginning of the numbers array. The result begins with the first element of numbers that does not satisfy predicate. let numbers = [3, 7, 4, -2, 9, -6, 10, 1] let startingWithNegative = numbers.drop(while: { $0 > 0 }) // startingWithNegative == [-2, 9, -6, 10, 1] If predicate matches every element in the sequence, the result is an empty sequence. Parameter predicate: A closure that takes an element of the sequence as its argument and returns a Boolean value indicating whether the element should be included in the result. Complexity: O(k), where k is the number of elements to drop from the beginning of the sequence. Declaration @inlinable public func drop(while predicate: (Self.Element) throws -> Bool) rethrows -> DropWhileSequence<Self> func drop(while predicate: (Self.Element) throws -> Bool) rethrows -> Self.SubSequence Required Returns a subsequence by skipping elements while predicate returns true and returning the remaining elements. Parameter predicate: A closure that takes an element of the sequence as its argument and returns true if the element should be skipped or false if it should be included. Once the predicate returns false it will not be called again. Complexity: O(n), where n is the length of the collection. Declaration @inlinable public func drop(while predicate: (Self.Element) throws -> Bool) rethrows -> Self.SubSequence func dropFirst(_ k: Int = 1) -> DropFirstSequence<Self> Required Returns a sequence containing all but the given number of initial elements. If the number of elements to drop exceeds the number of elements in the sequence, the result is an empty sequence. let numbers = [1, 2, 3, 4, 5] print(numbers.dropFirst(2)) // Prints "[3, 4, 5]" print(numbers.dropFirst(10)) // Prints "[]" Parameter k: The number of elements to drop from the beginning of the sequence. k must be greater than or equal to zero. Complexity: O(1), with O(k) deferred to each iteration of the result, where k is the number of elements to drop from the beginning of the sequence. Declaration @inlinable public func dropFirst(_ k: Int = 1) -> DropFirstSequence<Self> func dropFirst(_ k: Int = 1) -> Self.SubSequence Required Returns a subsequence containing all but the given number of initial elements. If the number of elements to drop exceeds the number of elements in the collection, the result is an empty subsequence. let numbers = [1, 2, 3, 4, 5] print(numbers.dropFirst(2)) // Prints "[3, 4, 5]" print(numbers.dropFirst(10)) // Prints "[]" Parameter k: The number of elements to drop from the beginning of the collection. k must be greater than or equal to zero. Complexity: O(1) if the collection conforms to RandomAccessCollection; otherwise, O(k), where k is the number of elements to drop from the beginning of the collection. Declaration @inlinable public func dropFirst(_ k: Int = 1) -> Self.SubSequence func dropLast(_ k: Int = 1) -> [Self.Element] Required Returns a sequence containing all but the given number of final elements. The sequence must be finite. If the number of elements to drop exceeds the number of elements in the sequence, the result is an empty sequence. let numbers = [1, 2, 3, 4, 5] print(numbers.dropLast(2)) // Prints "[1, 2, 3]" print(numbers.dropLast(10)) // Prints "[]" Parameter n: The number of elements to drop off the end of the sequence. n must be greater than or equal to zero. Complexity: O(n), where n is the length of the sequence. Declaration @inlinable public func dropLast(_ k: Int = 1) -> [Self.Element] func dropLast(_ k: Int = 1) -> Self.SubSequence Required Returns a subsequence containing all but the specified number of final elements. If the number of elements to drop exceeds the number of elements in the collection, the result is an empty subsequence. let numbers = [1, 2, 3, 4, 5] print(numbers.dropLast(2)) // Prints "[1, 2, 3]" print(numbers.dropLast(10)) // Prints "[]" Parameter k: The number of elements to drop off the end of the collection. k must be greater than or equal to zero. Complexity: O(1) if the collection conforms to RandomAccessCollection; otherwise, O(n), where n is the length of the collection. Declaration @inlinable public func dropLast(_ k: Int = 1) -> Self.SubSequence func elementsEqual(_ other: OtherSequence, by areEquivalent: (Self.Element, OtherSequence.Element) throws -> Bool) rethrows -> Bool Required Returns a Boolean value indicating whether this sequence and another sequence contain equivalent elements in the same order, using the given predicate as the equivalence test. At least one of the sequences must be finite. The predicate must be a equivalence relation over the elements. That is, for any elements a, b, and c, the following conditions must hold: Complexity: O(m), where m is the lesser of the length of the sequence and the length of other. Declaration @inlinable public func elementsEqual<OtherSequence>(_ other: OtherSequence, by areEquivalent: (Self.Element, OtherSequence.Element) throws -> Bool) rethrows -> Bool where OtherSequence: Sequence func enumerated() -> EnumeratedSequence<Self> Required Returns a sequence of pairs (n, x), where n represents a consecutive integer starting at zero and x represents an element of the sequence. This example enumerates the characters of the string "Swift" and prints each character along with its place in the string. for (n, c) in "Swift".enumerated() { print("\(n): '\(c)'") } // Prints "0: 'S'" // Prints "1: 'w'" // Prints "2: 'i'" // Prints "3: 'f'" // Prints "4: 't'" When you enumerate a collection, the integer part of each pair is a counter for the enumeration, but is not necessarily the index of the paired value. These counters can be used as indices only in instances of zero-based, integer-indexed collections, such as Array and ContiguousArray. For other collections the counters may be out of range or of the wrong type to use as an index. To iterate over the elements of a collection with its indices, use the zip(_:_:) function. This example iterates over the indices and elements of a set, building a list consisting of indices of names with five or fewer letters. let names: Set = ["Sofia", "Camilla", "Martina", "Mateo", "Nicolás"] var shorterIndices: [Set<String>.Index] = [] for (i, name) in zip(names.indices, names) { if name.count <= 5 { shorterIndices.append(i) } } Now that the shorterIndices array holds the indices of the shorter names in the names set, you can use those indices to access elements in the set. for i in shorterIndices { print(names[i]) } // Prints "Sofia" // Prints "Mateo" Complexity: O(1) Declaration @inlinable public func enumerated() -> EnumeratedSequence<Self> func filter(_ isIncluded: (Self.Element) throws -> Bool) rethrows -> [Self.Element] Required Returns an array containing, in order, the elements of the sequence that satisfy the given predicate. In this example, filter(_:) is used to include only names shorter than five characters. let cast = ["Vivien", "Marlon", "Kim", "Karl"] let shortNames = cast.filter { $0.count < 5 } print(shortNames) // Prints "["Kim", "Karl"]" Parameter isIncluded: A closure that takes an element of the sequence as its argument and returns a Boolean value indicating whether the element should be included in the returned array. Complexity: O(n), where n is the length of the sequence. Declaration @inlinable public func filter(_ isIncluded: (Self.Element) throws -> Bool) rethrows -> [Self.Element] func filter(_ isIncluded: (Dictionary<Key, Value>.Element) throws -> Bool) rethrows -> [Key : Value] Required Returns a new dictionary containing the key-value pairs of the dictionary that satisfy the given predicate. Parameter isIncluded: A closure that takes a key-value pair as its argument and returns a Boolean value indicating whether the pair should be included in the returned dictionary. Declaration @available(swift 4.0) @inlinable public func filter(_ isIncluded: (Dictionary<Key, Value>.Element) throws -> Bool) rethrows -> [Key : Value] func first(where predicate: (Self.Element) throws -> Bool) rethrows -> Self.Element? Required Returns the first element of the sequence that satisfies the given predicate. The following example uses the first(where:) method to find the first negative number in an array of integers: let numbers = [3, 7, 4, -2, 9, -6, 10, 1] if let firstNegative = numbers.first(where: { $0 < 0 }) { print("The first negative number is \(firstNegative).") } // Prints "The first negative number is -2." Parameter predicate: A closure that takes an element of the sequence as its argument and returns a Boolean value indicating whether the element is a match. Complexity: O(n), where n is the length of the sequence. Declaration @inlinable public func first(where predicate: (Self.Element) throws -> Bool) rethrows -> Self.Element? func firstIndex(where predicate: (Self.Element) throws -> Bool) rethrows -> Self.Index? Required Returns the first index in which an element of the collection satisfies the given predicate. You can use the predicate to find an element of a type that doesn't conform to the Equatable protocol or to find an element that matches particular criteria. Here's an example that finds a student name that begins with the letter "A": let students = ["Kofi", "Abena", "Peter", "Kweku", "Akosua"] if let i = students.firstIndex(where: { $0.hasPrefix("A") }) { print("\(students[i]) starts with 'A'!") } // Prints "Abena starts with 'A'!" Parameter predicate: A closure that takes an element as its argument and returns a Boolean value that indicates whether the passed element represents a match. Complexity: O(n), where n is the length of the collection. Declaration @inlinable public func firstIndex(where predicate: (Self.Element) throws -> Bool) rethrows -> Self.Index? func flatMap(_ transform: (Self.Element) throws -> SegmentOfResult) rethrows -> [SegmentOfResult.Element] Required Returns an array containing the concatenated results of calling the given transformation with each element of this sequence. Use this method to receive a single-level collection when your transformation produces a sequence or collection for each element. In this example, note the difference in the result of using map and flatMap with a transformation that returns an array. let numbers = [1, 2, 3, 4] let mapped = numbers.map { Array(repeating: $0, count: $0) } // [[1], [2, 2], [3, 3, 3], [4, 4, 4, 4]] let flatMapped = numbers.flatMap { Array(repeating: $0, count: $0) } // [1, 2, 2, 3, 3, 3, 4, 4, 4, 4] In fact, s.flatMap(transform) is equivalent to Array(s.map(transform).joined()). Parameter transform: A closure that accepts an element of this sequence as its argument and returns a sequence or collection. Complexity: O(m + n), where n is the length of this sequence and m is the length of the result. Declaration @inlinable public func flatMap<SegmentOfResult>(_ transform: (Self.Element) throws -> SegmentOfResult) rethrows -> [SegmentOfResult.Element] where SegmentOfResult: Sequence func flatMap(_ transform: (Self.Element) throws -> ElementOfResult?) rethrows -> [ElementOfResult] Required Declaration @available(swift, deprecated: 4.1, renamed: "compactMap(_:)", message: "Please use compactMap(_:) for the case where closure returns an optional value") public func flatMap<ElementOfResult>(_ transform: (Self.Element) throws -> ElementOfResult?) rethrows -> [ElementOfResult] func forEach(_ body: (Self.Element) throws -> Void) rethrows Required Calls the given closure on each element in the sequence in the same order as a for-in loop. The two loops in the following example produce the same output: let numberWords = ["one", "two", "three"] for word in numberWords { print(word) } // Prints "one" // Prints "two" // Prints "three" numberWords.forEach { word in print(word) } // Same as above Using the forEach method is distinct from a for-in loop in two important ways: You cannot use a break or continue statement to exit the current call of the body closure or skip subsequent calls. Using the return statement in the body closure will exit only from the current call to body, not from any outer scope, and won't skip subsequent calls. Parameter body: A closure that takes an element of the sequence as a parameter. Declaration @inlinable public func forEach(_ body: (Self.Element) throws -> Void) rethrows func formIndex(_ i: inout Self.Index, offsetBy distance: Int) Required Offsets the given index by the specified distance. The value passed as distance must not offset i beyond the bounds of the collection. Complexity: O(1) if the collection conforms to RandomAccessCollection; otherwise, O(k), where k is the absolute value of distance. Declaration @inlinable public func formIndex(_ i: inout Self.Index, offsetBy distance: Int) func formIndex(_ i: inout Self.Index, offsetBy distance: Int, limitedBy limit: Self.Index) -> Bool Required Offsets the given index by the specified distance, or so that it equals the given limiting index. The value passed as distance must not offset i beyond the bounds of the collection, unless the index passed as limit prevents offsetting beyond those bounds. Complexity: O(1) if the collection conforms to RandomAccessCollection; otherwise, O(k), where k is the absolute value of distance. Declaration @inlinable public func formIndex(_ i: inout Self.Index, offsetBy distance: Int, limitedBy limit: Self.Index) -> Bool func formIndex(after i: inout Dictionary<Key, Value>.Index) Required Replaces the given index with its successor. Parameter i: A valid index of the collection. i must be less than endIndex. Declaration @inlinable public func formIndex(after i: inout Dictionary<Key, Value>.Index) func formIndex(after i: inout Dictionary<Key, Value>.Index) Required Replaces the given index with its successor. Parameter i: A valid index of the collection. i must be less than endIndex. Declaration @inlinable public func formIndex(after i: inout Dictionary<Key, Value>.Index) func formIndex(after i: inout Self.Index) Required Replaces the given index with its successor. Parameter i: A valid index of the collection. i must be less than endIndex. Declaration @inlinable public func formIndex(after i: inout Self.Index) func formIndex(after i: inout Dictionary<Key, Value>.Index) Required Replaces the given index with its successor. Parameter i: A valid index of the collection. i must be less than endIndex. Declaration @inlinable public func formIndex(after i: inout Dictionary<Key, Value>.Index) func index(_ i: Self.Index, offsetBy distance: Int) -> Self.Index Required Returns an index that is the specified distance from the given index. The following example obtains an index advanced four positions from a string's starting index and then prints the character at that position. let s = "Swift" let i = s.index(s.startIndex, offsetBy: 4) print(s[i]) // Prints "t" The value passed as distance must not offset i beyond the bounds of the collection. Complexity: O(1) if the collection conforms to RandomAccessCollection; otherwise, O(k), where k is the absolute value of distance. Declaration @inlinable public func index(_ i: Self.Index, offsetBy distance: Int) -> Self.Index func index(_ i: Self.Index, offsetBy distance: Int, limitedBy limit: Self.Index) -> Self.Index? Required Returns an index that is the specified distance from the given index, unless that distance is beyond a given limiting index. The following example obtains an index advanced four positions from a string's starting index and then prints the character at that position. The operation doesn't require going beyond the limiting s.endIndex value, so it succeeds. let s = "Swift" if let i = s.index(s.startIndex, offsetBy: 4, limitedBy: s.endIndex) { print(s[i]) } // Prints "t" The next example attempts to retrieve an index six positions from s.startIndex but fails, because that distance is beyond the index passed as limit. let j = s.index(s.startIndex, offsetBy: 6, limitedBy: s.endIndex) print(j) // Prints "nil" The value passed as distance must not offset i beyond the bounds of the collection, unless the index passed as limit prevents offsetting beyond those bounds. Complexity: O(1) if the collection conforms to RandomAccessCollection; otherwise, O(k), where k is the absolute value of distance. Declaration @inlinable public func index(_ i: Self.Index, offsetBy distance: Int, limitedBy limit: Self.Index) -> Self.Index? func index(after i: Dictionary<Key, Value>.Index) -> Dictionary<Key, Value>.Index Required Returns the position immediately after the given index. The successor of an index must be well defined. For an index i into a collection c, calling c.index(after: i) returns the same index every time. Parameter i: A valid index of the collection. i must be less than endIndex. Declaration @inlinable public func index(after i: Dictionary<Key, Value>.Index) -> Dictionary<Key, Value>.Index func index(after i: Dictionary<Key, Value>.Index) -> Dictionary<Key, Value>.Index Required Returns the position immediately after the given index. The successor of an index must be well defined. For an index i into a collection c, calling c.index(after: i) returns the same index every time. Parameter i: A valid index of the collection. i must be less than endIndex. Declaration @inlinable public func index(after i: Dictionary<Key, Value>.Index) -> Dictionary<Key, Value>.Index func index(after i: Dictionary<Key, Value>.Index) -> Dictionary<Key, Value>.Index Required Returns the position immediately after the given index. The successor of an index must be well defined. For an index i into a collection c, calling c.index(after: i) returns the same index every time. Parameter i: A valid index of the collection. i must be less than endIndex. Declaration @inlinable public func index(after i: Dictionary<Key, Value>.Index) -> Dictionary<Key, Value>.Index func index(forKey key: Key) -> Dictionary<Key, Value>.Index? Required Returns the index for the given key. If the given key is found in the dictionary, this method returns an index into the dictionary that corresponds with the key-value pair. let countryCodes = ["BR": "Brazil", "GH": "Ghana", "JP": "Japan"] let index = countryCodes.index(forKey: "JP") print("Country code for \(countryCodes[index!].value): '\(countryCodes[index!].key)'.") // Prints "Country code for Japan: 'JP'." Parameter key: The key to find in the dictionary. Declaration @inlinable public func index(forKey key: Key) -> Dictionary<Key, Value>.Index? func lexicographicallyPrecedes(_ other: OtherSequence, by areInIncreasingOrder: (Self.Element, Self.Element) throws -> Bool) rethrows -> Bool Required Returns a Boolean value indicating whether the sequence precedes another sequence in a lexicographical (dictionary) ordering, using the given predicate to compare elements. The predicate must be a strict weak ordering over the elements. That is, for any elements a, b, and c, the following conditions must hold: Note: This method implements the mathematical notion of lexicographical ordering, which has no connection to Unicode. If you are sorting strings to present to the end user, use String APIs that perform localized comparison instead. Complexity: O(m), where m is the lesser of the length of the sequence and the length of other. Declaration @inlinable public func lexicographicallyPrecedes<OtherSequence>(_ other: OtherSequence, by areInIncreasingOrder: (Self.Element, Self.Element) throws -> Bool) rethrows -> Bool where OtherSequence: Sequence, Self.Element == OtherSequence.Element func makeIterator() -> Dictionary<Key, Value>.Iterator Required Returns an iterator over the dictionary's key-value pairs. Iterating over a dictionary yields the key-value pairs as two-element tuples. You can decompose the tuple in a for-in loop, which calls makeIterator() behind the scenes, or when calling the iterator's next() method directly. let hues = ["Heliotrope": 296, "Coral": 16, "Aquamarine": 156] for (name, hueValue) in hues { print("The hue of \(name) is \(hueValue).") } // Prints "The hue of Heliotrope is 296." // Prints "The hue of Coral is 16." // Prints "The hue of Aquamarine is 156." Declaration @inlinable public func makeIterator() -> Dictionary<Key, Value>.Iterator func map(_ transform: (Self.Element) throws -> T) rethrows -> [T] Required Returns an array containing the results of mapping the given closure over the sequence's elements. In this example, map is used first to convert the names in the array to lowercase strings and then to count their characters. let cast = ["Vivien", "Marlon", "Kim", "Karl"] let lowercaseNames = cast.map { $0.lowercased() } // 'lowercaseNames' == ["vivien", "marlon", "kim", "karl"] let letterCounts = cast.map { $0.count } // 'letterCounts' == [6, 6, 3, 4] Parameter transform: A mapping closure. transform accepts an element of this sequence as its parameter and returns a transformed value of the same or of a different type. Complexity: O(n), where n is the length of the sequence. Declaration @inlinable public func map<T>(_ transform: (Self.Element) throws -> T) rethrows -> [T] func map(_ transform: (Self.Element) throws -> T) rethrows -> [T] Required Returns an array containing the results of mapping the given closure over the sequence's elements. In this example, map is used first to convert the names in the array to lowercase strings and then to count their characters. let cast = ["Vivien", "Marlon", "Kim", "Karl"] let lowercaseNames = cast.map { $0.lowercased() } // 'lowercaseNames' == ["vivien", "marlon", "kim", "karl"] let letterCounts = cast.map { $0.count } // 'letterCounts' == [6, 6, 3, 4] Parameter transform: A mapping closure. transform accepts an element of this sequence as its parameter and returns a transformed value of the same or of a different type. Declaration @inlinable public func map<T>(_ transform: (Self.Element) throws -> T) rethrows -> [T] func mapValues(_ transform: (Value) throws -> T) rethrows -> [Key : T] Required Returns a new dictionary containing the keys of this dictionary with the values transformed by the given closure. Parameter transform: A closure that transforms a value. transform accepts each value of the dictionary as its parameter and returns a transformed value of the same or of a different type. Complexity: O(n), where n is the length of the dictionary. Declaration @inlinable public func mapValues<T>(_ transform: (Value) throws -> T) rethrows -> [Key : T] func max(by areInIncreasingOrder: (Self.Element, Self.Element) throws -> Bool) rethrows -> Self.Element? Required Returns the maximum element in the sequence, using the given predicate as the comparison between elements. The predicate must be a strict weak ordering over the elements. That is, for any elements a, b, and c, the following conditions must hold: This example shows how to use the max(by:) method on a dictionary to find the key-value pair with the highest value. let hues = ["Heliotrope": 296, "Coral": 16, "Aquamarine": 156] let greatestHue = hues.max { a, b in a.value < b.value } print(greatestHue) // Prints "Optional(("Heliotrope", 296))" Parameter areInIncreasingOrder: A predicate that returns true if its first argument should be ordered before its second argument; otherwise, false. Complexity: O(n), where n is the length of the sequence. Declaration @warn_unqualified_access @inlinable public func max(by areInIncreasingOrder: (Self.Element, Self.Element) throws -> Bool) rethrows -> Self.Element? func merge(_ other: S, uniquingKeysWith combine: (Value, Value) throws -> Value) rethrows Required Merges the key-value pairs in the given sequence into the dictionary, using a combining closure to determine the value for any duplicate keys. Use the combine closure to select a value to use in the updated dictionary, or to combine existing and new values. As the key-value pairs are merged with the dictionary, the combine closure is called with the current and new values for any duplicate keys that are encountered. This example shows how to choose the current or new values for any duplicate keys: var dictionary = ["a": 1, "b": 2] // Keeping existing value for key "a": dictionary.merge(zip(["a", "c"], [3, 4])) { (current, _) in current } // ["b": 2, "a": 1, "c": 4] // Taking the new value for key "a": dictionary.merge(zip(["a", "d"], [5, 6])) { (_, new) in new } // ["b": 2, "a": 5, "c": 4, "d": 6] Declaration @inlinable public mutating func merge<S>(_ other: S, uniquingKeysWith combine: (Value, Value) throws -> Value) rethrows where S: Sequence, S.Element == (Key, Value) func merge(_ other: [Key : Value], uniquingKeysWith combine: (Value, Value) throws -> Value) rethrows Required Merges the given dictionary into this dictionary, using a combining closure to determine the value for any duplicate keys. Use the combine closure to select a value to use in the updated dictionary, or to combine existing and new values. As the key-values pairs in other are merged with this dictionary, the combine closure is called with the current and new values for any duplicate keys that are encountered. This example shows how to choose the current or new values for any duplicate keys: var dictionary = ["a": 1, "b": 2] // Keeping existing value for key "a": dictionary.merge(["a": 3, "c": 4]) { (current, _) in current } // ["b": 2, "a": 1, "c": 4] // Taking the new value for key "a": dictionary.merge(["a": 5, "d": 6]) { (_, new) in new } // ["b": 2, "a": 5, "c": 4, "d": 6] Declaration @inlinable public mutating func merge(_ other: [Key : Value], uniquingKeysWith combine: (Value, Value) throws -> Value) rethrows func merging(_ other: S, uniquingKeysWith combine: (Value, Value) throws -> Value) rethrows -> [Key : Value] Required Creates a dictionary by merging key-value pairs in a sequence into the dictionary, using a combining closure to determine the value for duplicate keys. Use the combine closure to select a value to use in the returned dictionary, or to combine existing and new values. As the key-value pairs are merged with the dictionary, the combine closure is called with the current and new values for any duplicate keys that are encountered. This example shows how to choose the current or new values for any duplicate keys: let dictionary = ["a": 1, "b": 2] let newKeyValues = zip(["a", "b"], [3, 4]) let keepingCurrent = dictionary.merging(newKeyValues) { (current, _) in current } // ["b": 2, "a": 1] let replacingCurrent = dictionary.merging(newKeyValues) { (_, new) in new } // ["b": 4, "a": 3] Declaration @inlinable public func merging<S>(_ other: S, uniquingKeysWith combine: (Value, Value) throws -> Value) rethrows -> [Key : Value] where S: Sequence, S.Element == (Key, Value) func merging(_ other: [Key : Value], uniquingKeysWith combine: (Value, Value) throws -> Value) rethrows -> [Key : Value] Required Creates a dictionary by merging the given dictionary into this dictionary, using a combining closure to determine the value for duplicate keys. Use the combine closure to select a value to use in the returned dictionary, or to combine existing and new values. As the key-value pairs in other are merged with this dictionary, the combine closure is called with the current and new values for any duplicate keys that are encountered. This example shows how to choose the current or new values for any duplicate keys: let dictionary = ["a": 1, "b": 2] let otherDictionary = ["a": 3, "b": 4] let keepingCurrent = dictionary.merging(otherDictionary) { (current, _) in current } // ["b": 2, "a": 1] let replacingCurrent = dictionary.merging(otherDictionary) { (_, new) in new } // ["b": 4, "a": 3] Declaration @inlinable public func merging(_ other: [Key : Value], uniquingKeysWith combine: (Value, Value) throws -> Value) rethrows -> [Key : Value] func min(by areInIncreasingOrder: (Self.Element, Self.Element) throws -> Bool) rethrows -> Self.Element? Required Returns the minimum element in the sequence, using the given predicate as the comparison between elements. The predicate must be a strict weak ordering over the elements. That is, for any elements a, b, and c, the following conditions must hold: This example shows how to use the min(by:) method on a dictionary to find the key-value pair with the lowest value. let hues = ["Heliotrope": 296, "Coral": 16, "Aquamarine": 156] let leastHue = hues.min { a, b in a.value < b.value } print(leastHue) // Prints "Optional(("Coral", 16))" Parameter areInIncreasingOrder: A predicate that returns true if its first argument should be ordered before its second argument; otherwise, false. Complexity: O(n), where n is the length of the sequence. Declaration @warn_unqualified_access @inlinable public func min(by areInIncreasingOrder: (Self.Element, Self.Element) throws -> Bool) rethrows -> Self.Element? func popFirst() -> Dictionary<Key, Value>.Element? Required Removes and returns the first key-value pair of the dictionary if the dictionary isn't empty. The first element of the dictionary is not necessarily the first element added. Don't expect any particular ordering of key-value pairs. Complexity: Averages to O(1) over many calls to popFirst(). Declaration @inlinable public mutating func popFirst() -> Dictionary<Key, Value>.Element? func prefix(_ maxLength: Int) -> PrefixSequence<Self> Required Returns a sequence, up to the specified maximum length, containing the initial elements of the sequence. If the maximum length exceeds the number of elements in the sequence, the result contains all the elements in the sequence. let numbers = [1, 2, 3, 4, 5] print(numbers.prefix(2)) // Prints "[1, 2]" print(numbers.prefix(10)) // Prints "[1, 2, 3, 4, 5]" Parameter maxLength: The maximum number of elements to return. The value of maxLength must be greater than or equal to zero. Complexity: O(1) Declaration @inlinable public func prefix(_ maxLength: Int) -> PrefixSequence<Self> func prefix(_ maxLength: Int) -> Self.SubSequence Required Returns a subsequence, up to the specified maximum length, containing the initial elements of the collection. If the maximum length exceeds the number of elements in the collection, the result contains all the elements in the collection. let numbers = [1, 2, 3, 4, 5] print(numbers.prefix(2)) // Prints "[1, 2]" print(numbers.prefix(10)) // Prints "[1, 2, 3, 4, 5]" Parameter maxLength: The maximum number of elements to return. maxLength must be greater than or equal to zero. Complexity: O(1) if the collection conforms to RandomAccessCollection; otherwise, O(k), where k is the number of elements to select from the beginning of the collection. Declaration @inlinable public func prefix(_ maxLength: Int) -> Self.SubSequence func prefix(through position: Self.Index) -> Self.SubSequence Required Returns a subsequence from the start of the collection through the specified position. The resulting subsequence includes the element at the position end. The following example searches for the index of the number 40 in an array of integers, and then prints the prefix of the array up to, and including, that index: let numbers = [10, 20, 30, 40, 50, 60] if let i = numbers.firstIndex(of: 40) { print(numbers.prefix(through: i)) } // Prints "[10, 20, 30, 40]" Using the prefix(through:) method is equivalent to using a partial closed range as the collection's subscript. The subscript notation is preferred over prefix(through:). if let i = numbers.firstIndex(of: 40) { print(numbers[...i]) } // Prints "[10, 20, 30, 40]" Parameter end: The index of the last element to include in the resulting subsequence. end must be a valid index of the collection that is not equal to the endIndex property. Complexity: O(1) Declaration @inlinable public func prefix(through position: Self.Index) -> Self.SubSequence func prefix(upTo end: Self.Index) -> Self.SubSequence Required Returns a subsequence from the start of the collection up to, but not including, the specified position. The resulting subsequence does not include the element at the position end. The following example searches for the index of the number 40 in an array of integers, and then prints the prefix of the array up to, but not including, that index: let numbers = [10, 20, 30, 40, 50, 60] if let i = numbers.firstIndex(of: 40) { print(numbers.prefix(upTo: i)) } // Prints "[10, 20, 30]" Passing the collection's starting index as the end parameter results in an empty subsequence. print(numbers.prefix(upTo: numbers.startIndex)) // Prints "[]" Using the prefix(upTo:) method is equivalent to using a partial half-open range as the collection's subscript. The subscript notation is preferred over prefix(upTo:). if let i = numbers.firstIndex(of: 40) { print(numbers[..<i]) } // Prints "[10, 20, 30]" Parameter end: The "past the end" index of the resulting subsequence. end must be a valid index of the collection. Complexity: O(1) Declaration @inlinable public func prefix(upTo end: Self.Index) -> Self.SubSequence func prefix(while predicate: (Self.Element) throws -> Bool) rethrows -> [Self.Element] Required Returns a sequence containing the initial, consecutive elements that satisfy the given predicate. The following example uses the prefix(while:) method to find the positive numbers at the beginning of the numbers array. Every element of numbers up to, but not including, the first negative value is included in the result. let numbers = [3, 7, 4, -2, 9, -6, 10, 1] let positivePrefix = numbers.prefix(while: { $0 > 0 }) // positivePrefix == [3, 7, 4] If predicate matches every element in the sequence, the resulting sequence contains every element of the sequence. Parameter predicate: A closure that takes an element of the sequence as its argument and returns a Boolean value indicating whether the element should be included in the result. Complexity: O(k), where k is the length of the result. Declaration @inlinable public func prefix(while predicate: (Self.Element) throws -> Bool) rethrows -> [Self.Element] func prefix(while predicate: (Self.Element) throws -> Bool) rethrows -> Self.SubSequence Required Returns a subsequence containing the initial elements until predicate returns false and skipping the remaining elements. Parameter predicate: A closure that takes an element of the sequence as its argument and returns true if the element should be included or false if it should be excluded. Once the predicate returns false it will not be called again. Complexity: O(n), where n is the length of the collection. Declaration @inlinable public func prefix(while predicate: (Self.Element) throws -> Bool) rethrows -> Self.SubSequence func randomElement() -> Self.Element? Required Returns a random element of the collection. Call randomElement() to select a random element from an array or another collection. This example picks a name at random from an array: let names = ["Zoey", "Chloe", "Amani", "Amaia"] let randomName = names.randomElement()! // randomName == "Amani" This method is equivalent to calling randomElement(using:), passing in the system's default random generator. Complexity: O(1) if the collection conforms to RandomAccessCollection; otherwise, O(n), where n is the length of the collection. Declaration @inlinable public func randomElement() -> Self.Element? func randomElement(using generator: inout T) -> Self.Element? Required Returns a random element of the collection, using the given generator as a source for randomness. Call randomElement(using:) to select a random element from an array or another collection when you are using a custom random number generator. This example picks a name at random from an array: let names = ["Zoey", "Chloe", "Amani", "Amaia"] let randomName = names.randomElement(using: &myGenerator)! // randomName == "Amani" Parameter generator: The random number generator to use when choosing a random element. Complexity: O(1) if the collection conforms to RandomAccessCollection; otherwise, O(n), where n is the length of the collection. Note: The algorithm used to select a random element may change in a future version of Swift. If you're passing a generator that results in the same sequence of elements each time you run your program, that sequence may change when your program is compiled using a different version of Swift. Declaration @inlinable public func randomElement<T>(using generator: inout T) -> Self.Element? where T: RandomNumberGenerator func reduce(_ initialResult: Result, _ nextPartialResult: (Result, Self.Element) throws -> Result) rethrows -> Result Required Returns the result of combining the elements of the sequence using the given closure. Use the reduce(_:_:) method to produce a single value from the elements of an entire sequence. For example, you can use this method on an array of numbers to find their sum or product. The nextPartialResult closure is called sequentially with an accumulating value initialized to initialResult and each element of the sequence. This example shows how to find the sum of an array of numbers. let numbers = [1, 2, 3, 4] let numberSum = numbers.reduce(0, { x, y in x + y }) // numberSum == 10 When numbers.reduce(_:_:) is called, the following steps occur: The nextPartialResult closure is called with initialResult---0 in this case---and the first element of numbers, returning the sum: 1. The closure is called again repeatedly with the previous call's return value and each element of the sequence. When the sequence is exhausted, the last value returned from the closure is returned to the caller. If the sequence has no elements, nextPartialResult is never executed and initialResult is the result of the call to reduce(_:_:). Complexity: O(n), where n is the length of the sequence. Declaration @inlinable public func reduce<Result>(_ initialResult: Result, _ nextPartialResult: (Result, Self.Element) throws -> Result) rethrows -> Result func reduce(into initialResult: Result, _ updateAccumulatingResult: (inout Result, Self.Element) throws -> ()) rethrows -> Result Required Returns the result of combining the elements of the sequence using the given closure. Use the reduce(into:_:) method to produce a single value from the elements of an entire sequence. For example, you can use this method on an array of integers to filter adjacent equal entries or count frequencies. This method is preferred over reduce(_:_:) for efficiency when the result is a copy-on-write type, for example an Array or a Dictionary. The updateAccumulatingResult closure is called sequentially with a mutable accumulating value initialized to initialResult and each element of the sequence. This example shows how to build a dictionary of letter frequencies of a string. let letters = "abracadabra" let letterCount = letters.reduce(into: [:]) { counts, letter in counts[letter, default: 0] += 1 } // letterCount == ["a": 5, "b": 2, "r": 2, "c": 1, "d": 1] When letters.reduce(into:_:) is called, the following steps occur: The updateAccumulatingResult closure is called with the initial accumulating value---[:] in this case---and the first character of letters, modifying the accumulating value by setting 1 for the key "a". The closure is called again repeatedly with the updated accumulating value and each element of the sequence. When the sequence is exhausted, the accumulating value is returned to the caller. If the sequence has no elements, updateAccumulatingResult is never executed and initialResult is the result of the call to reduce(into:_:). Complexity: O(n), where n is the length of the sequence. Declaration @inlinable public func reduce<Result>(into initialResult: Result, _ updateAccumulatingResult: (inout Result, Self.Element) throws -> ()) rethrows -> Result func remove(at index: Dictionary<Key, Value>.Index) -> Dictionary<Key, Value>.Element Required Removes and returns the key-value pair at the specified index. Calling this method invalidates any existing indices for use with this dictionary. Parameter index: The position of the key-value pair to remove. index must be a valid index of the dictionary, and must not equal the dictionary's end index. Complexity: O(n), where n is the number of key-value pairs in the dictionary. Declaration @inlinable public mutating func remove(at index: Dictionary<Key, Value>.Index) -> Dictionary<Key, Value>.Element func removeAll(keepingCapacity keepCapacity: Bool = false) Required Removes all key-value pairs from the dictionary. Calling this method invalidates all indices with respect to the dictionary. Parameter keepCapacity: Whether the dictionary should keep its underlying buffer. If you pass true, the operation preserves the buffer capacity that the collection has, otherwise the underlying buffer is released. The default is false. Complexity: O(n), where n is the number of key-value pairs in the dictionary. Declaration @inlinable public mutating func removeAll(keepingCapacity keepCapacity: Bool = false) func removeValue(forKey key: Key) -> Value? Required Removes the given key and its associated value from the dictionary. If the key is found in the dictionary, this method returns the key's associated value. On removal, this method invalidates all indices with respect to the dictionary. var hues = ["Heliotrope": 296, "Coral": 16, "Aquamarine": 156] if let value = hues.removeValue(forKey: "Coral") { print("The value \(value) was removed.") } // Prints "The value 16 was removed." If the key isn't found in the dictionary, removeValue(forKey:) returns nil. if let value = hues.removeValueForKey("Cerise") { print("The value \(value) was removed.") } else { print("No value found for that key.") } // Prints "No value found for that key."" Parameter key: The key to remove along with its associated value. Complexity: O(n), where n is the number of key-value pairs in the dictionary. Declaration @inlinable public mutating func removeValue(forKey key: Key) -> Value? func reserveCapacity(_ minimumCapacity: Int) Required Reserves enough space to store the specified number of key-value pairs. If you are adding a known number of key-value pairs to a dictionary, use this method to avoid multiple reallocations. This method ensures that the dictionary has unique, mutable, contiguous storage, with space allocated for at least the requested number of key-value pairs. Calling the reserveCapacity(_:) method on a dictionary with bridged storage triggers a copy to contiguous storage even if the existing storage has room to store minimumCapacity key-value pairs. Parameter minimumCapacity: The requested number of key-value pairs to store. Declaration public mutating func reserveCapacity(_ minimumCapacity: Int) func reversed() -> [Self.Element] Required Returns an array containing the elements of this sequence in reverse order. The sequence must be finite. Complexity: O(n), where n is the length of the sequence. Declaration @inlinable public func reversed() -> [Self.Element] func shuffled() -> [Self.Element] Required Returns the elements of the sequence, shuffled. For example, you can shuffle the numbers between 0 and 9 by calling the shuffled() method on that range: let numbers = 0...9 let shuffledNumbers = numbers.shuffled() // shuffledNumbers == [1, 7, 6, 2, 8, 9, 4, 3, 5, 0] This method is equivalent to calling shuffled(using:), passing in the system's default random generator. Complexity: O(n), where n is the length of the sequence. Declaration @inlinable public func shuffled() -> [Self.Element] func shuffled(using generator: inout T) -> [Self.Element] Required Returns the elements of the sequence, shuffled using the given generator as a source for randomness. You use this method to randomize the elements of a sequence when you are using a custom random number generator. For example, you can shuffle the numbers between 0 and 9 by calling the shuffled(using:) method on that range: let numbers = 0...9 let shuffledNumbers = numbers.shuffled(using: &myGenerator) // shuffledNumbers == [8, 9, 4, 3, 2, 6, 7, 0, 5, 1] Parameter generator: The random number generator to use when shuffling the sequence. Complexity: O(n), where n is the length of the sequence. Note: The algorithm used to shuffle a sequence may change in a future version of Swift. If you're passing a generator that results in the same shuffled order each time you run your program, that sequence may change when your program is compiled using a different version of Swift. Declaration @inlinable public func shuffled<T>(using generator: inout T) -> [Self.Element] where T: RandomNumberGenerator func sorted(by areInIncreasingOrder: (Self.Element, Self.Element) throws -> Bool) rethrows -> [Self.Element] Required Returns the elements of the sequence, sorted using the given predicate as the comparison between elements. When you want to sort a sequence of elements that don't conform to the Comparable protocol, pass a predicate to this method that returns true when the first element should be ordered before the second. The elements of the resulting array are ordered according to the given predicate. In the following example, the predicate provides an ordering for an array of a custom HTTPResponse type. The predicate orders errors before successes and sorts the error responses by their error code. enum HTTPResponse { case ok case error(Int) } let responses: [HTTPResponse] = [.error(500), .ok, .ok, .error(404), .error(403)] let sortedResponses = responses.sorted { switch ($0, $1) { // Order errors by code case let (.error(aCode), .error(bCode)): return aCode < bCode // All successes are equivalent, so none is before any other case (.ok, .ok): return false // Order errors before successes case (.error, .ok): return true case (.ok, .error): return false } } print(sortedResponses) // Prints "[.error(403), .error(404), .error(500), .ok, .ok]" You also use this method to sort elements that conform to the Comparable protocol in descending order. To sort your sequence in descending order, pass the greater-than operator (>) as the areInIncreasingOrder parameter. let students: Set = ["Kofi", "Abena", "Peter", "Kweku", "Akosua"] let descendingStudents = students.sorted(by: >) print(descendingStudents) // Prints "["Peter", "Kweku", "Kofi", "Akosua", "Abena"]" Calling the related sorted() method is equivalent to calling this method and passing the less-than operator (<) as the predicate. print(students.sorted()) // Prints "["Abena", "Akosua", "Kofi", "Kweku", "Peter"]" print(students.sorted(by: <)) // Prints "["Abena", "Akosua", "Kofi", "Kweku", "Peter"]" The predicate must be a strict weak ordering over the elements. That is, for any elements a, b, and c, the following conditions must hold: The sorting algorithm is not guaranteed to be stable. A stable sort preserves the relative order of elements for which areInIncreasingOrder does not establish an order. Parameter areInIncreasingOrder: A predicate that returns true if its first argument should be ordered before its second argument; otherwise, false. Complexity: O(n log n), where n is the length of the sequence. Declaration @inlinable public func sorted(by areInIncreasingOrder: (Self.Element, Self.Element) throws -> Bool) rethrows -> [Self.Element] func split(maxSplits: Int = Int.max, omittingEmptySubsequences: Bool = true, whereSeparator isSeparator: (Self.Element) throws -> Bool) rethrows -> [ArraySlice<Self.Element>] Required Returns the longest possible subsequences of the sequence, in order, that don't contain elements satisfying the given predicate. Elements that are used to split the sequence are not returned as part of any subsequence. The following examples show the effects of the maxSplits and omittingEmptySubsequences parameters when splitting a string using a closure that matches spaces. The first use of split returns each word that was originally separated by one or more spaces. let line = "BLANCHE: I don't want realism. I want magic!" print(line.split(whereSeparator: { $0 == " " }) .map(String.init)) // Prints "["BLANCHE:", "I", "don\'t", "want", "realism.", "I", "want", "magic!"]" The second example passes 1 for the maxSplits parameter, so the original string is split just once, into two new strings. print( line.split(maxSplits: 1, whereSeparator: { $0 == " " }) .map(String.init)) // Prints "["BLANCHE:", " I don\'t want realism. I want magic!"]" The final example passes true for the allowEmptySlices parameter, so the returned array contains empty strings where spaces were repeated. print( line.split( omittingEmptySubsequences: false, whereSeparator: { $0 == " " } ).map(String.init)) // Prints "["BLANCHE:", "", "", "I", "don\'t", "want", "realism.", "I", "want", "magic!"]" Complexity: O(n), where n is the length of the sequence. Declaration @inlinable public func split(maxSplits: Int = Int.max, omittingEmptySubsequences: Bool = true, whereSeparator isSeparator: (Self.Element) throws -> Bool) rethrows -> [ArraySlice<Self.Element>] func split(maxSplits: Int = Int.max, omittingEmptySubsequences: Bool = true, whereSeparator isSeparator: (Self.Element) throws -> Bool) rethrows -> [Self.SubSequence] Required Returns the longest possible subsequences of the collection, in order, that don't contain elements satisfying the given predicate. The resulting array consists of at most maxSplits + 1 subsequences. Elements that are used to split the sequence are not returned as part of any subsequence. The following examples show the effects of the maxSplits and omittingEmptySubsequences parameters when splitting a string using a closure that matches spaces. The first use of split returns each word that was originally separated by one or more spaces. let line = "BLANCHE: I don't want realism. I want magic!" print(line.split(whereSeparator: { $0 == " " })) // Prints "["BLANCHE:", "I", "don\'t", "want", "realism.", "I", "want", "magic!"]" The second example passes 1 for the maxSplits parameter, so the original string is split just once, into two new strings. print(line.split(maxSplits: 1, whereSeparator: { $0 == " " })) // Prints "["BLANCHE:", " I don\'t want realism. I want magic!"]" The final example passes false for the omittingEmptySubsequences parameter, so the returned array contains empty strings where spaces were repeated. print(line.split(omittingEmptySubsequences: false, whereSeparator: { $0 == " " })) // Prints "["BLANCHE:", "", "", "I", "don\'t", "want", "realism.", "I", "want", "magic!"]" Complexity: O(n), where n is the length of the collection. Declaration @inlinable public func split(maxSplits: Int = Int.max, omittingEmptySubsequences: Bool = true, whereSeparator isSeparator: (Self.Element) throws -> Bool) rethrows -> [Self.SubSequence] func starts(with possiblePrefix: PossiblePrefix, by areEquivalent: (Self.Element, PossiblePrefix.Element) throws -> Bool) rethrows -> Bool Required Returns a Boolean value indicating whether the initial elements of the sequence are equivalent to the elements in another sequence, using the given predicate as the equivalence test. The predicate must be a equivalence relation over the elements. That is, for any elements a, b, and c, the following conditions must hold: Complexity: O(m), where m is the lesser of the length of the sequence and the length of possiblePrefix. Declaration @inlinable public func starts<PossiblePrefix>(with possiblePrefix: PossiblePrefix, by areEquivalent: (Self.Element, PossiblePrefix.Element) throws -> Bool) rethrows -> Bool where PossiblePrefix: Sequence func suffix(_ maxLength: Int) -> [Self.Element] Required Returns a subsequence, up to the given maximum length, containing the final elements of the sequence. The sequence must be finite. If the maximum length exceeds the number of elements in the sequence, the result contains all the elements in the sequence. let numbers = [1, 2, 3, 4, 5] print(numbers.suffix(2)) // Prints "[4, 5]" print(numbers.suffix(10)) // Prints "[1, 2, 3, 4, 5]" Parameter maxLength: The maximum number of elements to return. The value of maxLength must be greater than or equal to zero. Complexity: O(n), where n is the length of the sequence. Declaration @inlinable public func suffix(_ maxLength: Int) -> [Self.Element] func suffix(_ maxLength: Int) -> Self.SubSequence Required Returns a subsequence, up to the given maximum length, containing the final elements of the collection. If the maximum length exceeds the number of elements in the collection, the result contains all the elements in the collection. let numbers = [1, 2, 3, 4, 5] print(numbers.suffix(2)) // Prints "[4, 5]" print(numbers.suffix(10)) // Prints "[1, 2, 3, 4, 5]" Parameter maxLength: The maximum number of elements to return. The value of maxLength must be greater than or equal to zero. Complexity: O(1) if the collection conforms to RandomAccessCollection; otherwise, O(n), where n is the length of the collection. Declaration @inlinable public func suffix(_ maxLength: Int) -> Self.SubSequence func suffix(from start: Self.Index) -> Self.SubSequence Required Returns a subsequence from the specified position to the end of the collection. The following example searches for the index of the number 40 in an array of integers, and then prints the suffix of the array starting at that index: let numbers = [10, 20, 30, 40, 50, 60] if let i = numbers.firstIndex(of: 40) { print(numbers.suffix(from: i)) } // Prints "[40, 50, 60]" Passing the collection's endIndex as the start parameter results in an empty subsequence. print(numbers.suffix(from: numbers.endIndex)) // Prints "[]" Using the suffix(from:) method is equivalent to using a partial range from the index as the collection's subscript. The subscript notation is preferred over suffix(from:). if let i = numbers.firstIndex(of: 40) { print(numbers[i...]) } // Prints "[40, 50, 60]" Parameter start: The index at which to start the resulting subsequence. start must be a valid index of the collection. Complexity: O(1) Declaration @inlinable public func suffix(from start: Self.Index) -> Self.SubSequence func swapAt(_ i: Dictionary<Key, Value>.Index, _ j: Dictionary<Key, Value>.Index) Required Exchanges the values at the specified indices of the collection. Both parameters must be valid indices of the collection and not equal to endIndex. Passing the same index as both i and j has no effect. Complexity: O(1) Declaration @inlinable public mutating func swapAt(_ i: Dictionary<Key, Value>.Index, _ j: Dictionary<Key, Value>.Index) func updateValue(_ value: Value, forKey key: Key) -> Value? Required Updates the value stored in the dictionary for the given key, or adds a new key-value pair if the key does not exist. Use this method instead of key-based subscripting when you need to know whether the new value supplants the value of an existing key. If the value of an existing key is updated, updateValue(_:forKey:) returns the original value. var hues = ["Heliotrope": 296, "Coral": 16, "Aquamarine": 156] if let oldValue = hues.updateValue(18, forKey: "Coral") { print("The old value of \(oldValue) was replaced with a new one.") } // Prints "The old value of 16 was replaced with a new one." If the given key is not present in the dictionary, this method adds the key-value pair and returns nil. if let oldValue = hues.updateValue(330, forKey: "Cerise") { print("The old value of \(oldValue) was replaced with a new one.") } else { print("No value was found in the dictionary for that key.") } // Prints "No value was found in the dictionary for that key." Declaration @inlinable public mutating func updateValue(_ value: Value, forKey key: Key) -> Value? func withContiguousStorageIfAvailable(_ body: (UnsafeBufferPointer<Self.Element>) throws -> R) rethrows -> R? Required Call body(p), where p is a pointer to the collection's contiguous storage. If no such storage exists, it is first created. If the collection does not support an internal representation in a form of contiguous storage, body is not called and nil is returned. A Collection that provides its own implementation of this method must also guarantee that an equivalent buffer of its SubSequence can be generated by advancing the pointer by the distance to the slice's startIndex. Declaration @inlinable public func withContiguousStorageIfAvailable<R>(_ body: (UnsafeBufferPointer<Self.Element>) throws -> R) rethrows -> R? Type Methods func ==(lhs: Dictionary<Key, Value>.Keys, rhs: Dictionary<Key, Value>.Keys) -> Bool Required Returns a Boolean value indicating whether two values are equal. Equality is the inverse of inequality. For any values a and b, a == b implies that a != b is false. Declaration @inlinable public static func ==(lhs: Dictionary<Key, Value>.Keys, rhs: Dictionary<Key, Value>.Keys) -> Bool